SOLUTION: 1+2*(3-4)^2 = -5*(-2+4)^2(2^3/4) = thnaks in advance :)
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-> SOLUTION: 1+2*(3-4)^2 = -5*(-2+4)^2(2^3/4) = thnaks in advance :)
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Question 967648
:
1+2*(3-4)^2 =
-5*(-2+4)^2(2^3/4) =
thnaks in advance :)
Answer by
rfer(16322)
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1+2*(3-4)^2=
1+2*1=3
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-5*(-2+4)^2(2^3/4)=
-5*(4)(1.68)=-33.6