SOLUTION: f. (-10)+(56*10)-(3)5+(-10*-2) h. [(4 – 18) * (13 - 14)] / 14 i. {[((-140*-20)/70)*5]/20} j. [(-10)4*(-5)3]/50 como se resuelve esto?

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: f. (-10)+(56*10)-(3)5+(-10*-2) h. [(4 – 18) * (13 - 14)] / 14 i. {[((-140*-20)/70)*5]/20} j. [(-10)4*(-5)3]/50 como se resuelve esto?       Log On


   

Question 957296: f. (-10)+(56*10)-(3)5+(-10*-2)
h. [(4 – 18) * (13 - 14)] / 14
i. {[((-140*-20)/70)*5]/20}
j. [(-10)4*(-5)3]/50
como se resuelve esto?
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

f.
%28-10%29%2B%2856%2A10%29-%283%295%2B%28-10%2A-2%29.....(recall:minus*minus=plus, minus*plus=minus)
=-10%2B560-15%2B20
=560%2B20-10-15
=%28560%2B20%29-%2810%2B15%29
=580-25
=555
h.
%28%284+-18%29+%2A+%2813+-14%29%29+%2F+14
=%28%28+-14%29+%2A+%28+-1%29%29+%2F+14
=14+%2F+14
=1
i.
%28%28%28-140%2A-20%29%2F70%29%2A5%29%2F20
=%28%282800%2F70%29%2A5%29%2F20
=%2840%2A5%29%2F20
=200%2F20
=10
j.
%28%28-10%294%2A%28-5%293%29%2F50
=%28%28-40%29%2A%28-15%29%29%2F50
=600%2F50
=12