SOLUTION: there are twice as many boys in a room as girls. if 5 boys leave the room, there would be a equal number of boys and girls in the room. how many boys were in the room at first.

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: there are twice as many boys in a room as girls. if 5 boys leave the room, there would be a equal number of boys and girls in the room. how many boys were in the room at first.      Log On


   



Question 938790: there are twice as many boys in a room as girls. if 5 boys leave the room, there would be a equal number of boys and girls in the room. how many boys were in the room at first.
Found 2 solutions by ewatrrr, Edwin McCravy:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
for Ex
10boys and 5girls
5 boys leave
5 = 5
...
10boys originally

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
Without using algebra:

Since there were twice as many boys as girls, think of dividing the
boys into two equal groups, and letting all the girls be a third group.
Then each of those 3 groups would have the same number of people. 

Then if 1 of those groups of boys left the room, there would be just two
equal groups, one of boys and 1 or girls.  

So the 5 boys that left must have been one of those groups.  So at first,
there were 10 boys and 5 girls in the room.

    
Using algebra:

system%28b+=+2g%2Cb-5=g%29

Substitute (2g) for b in the second equation:

b-5=g
2g-5=g
g=5

Substitute (5) for g in b=2g

b=2%285%29=10

10 boys and 5 girls in the room at first.

Edwin