Question 923674: The length of a rectangle is 5 ft longer than twice the width. if the perimeter is 100ft, find the length and width of the rectangle. Answer by Roseghanezadeh(16) (Show Source):
You can put this solution on YOUR website! Let's give the width the variable "w" and the length the variable "l". So it says that the length of a rectangle is 5 ft longer than twice the width which we can write as "5 + 2w". And that its perimeter = 100ft.
We know the formula for the perimeter of a rectangle is:
2l + 2w = p
Now we substitute:
2(5 + 2w) + 2w = 100
10 + 4w + 2w = 100
Now we take like terms to one side:
6w = 90
w = 15ft
We also knew that "l = 5 + 2w", so:
l = 5 + 2(15)
l = 35ft
Check with the formula "2l + 2w = p"
2(35) + 2(15) = 100
70 + 30 = 100
100 = 100
(