SOLUTION: 1 over(x+h)^2 minus 1 over x^2 all this over h. I have the solutions manual but I don't now how they got x^2-(x+h)^2 for the numerator after mult. by LCD. What happened to the 1

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: 1 over(x+h)^2 minus 1 over x^2 all this over h. I have the solutions manual but I don't now how they got x^2-(x+h)^2 for the numerator after mult. by LCD. What happened to the 1      Log On


   

Question 84324This question is from textbook Coll. Alg. Graphing Approach
: 1 over(x+h)^2 minus 1 over x^2 all this over h. I have the solutions manual but I don't now how they got x^2-(x+h)^2 for the numerator after mult. by LCD. What happened to the 1's in the original numerator? Thank you! Jackie This question is from textbook Coll. Alg. Graphing Approach

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
%281+%2F%28%28x%2Bh%29%5E2%29+-+1+%2F%28+x%5E2%29%29+%2Fh

It may help to write this in a different format:
1+%2F%28%28x%2Bh%29%5E2%29+-+1+%2F%28+x%5E2%29+ DIVIDED BY h
%281+%2F%28%28x%2Bh%29%5E2%29+-+1+%2F%28+x%5E2%29%29%2A+%281%2Fh%29

Now, you have to get the common denominator x%5E2%28x%2Bh%29%5E2 before you can subtract the first two fractions:


It's hairy, but this is why your numerator is +1%2Ax%5E2+-+1%2A%28x%2Bh%29%5E2+, over the common denominator (times h, of course).

R^2 at SCC