SOLUTION: Hi, Could you please help me solve the below problem. Much appreciate your help. Thank you very much for your time and help. regards Simsasha Four parcels have a total weight

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Question 828461: Hi,
Could you please help me solve the below problem. Much appreciate your help. Thank you very much for your time and help.
regards
Simsasha
Four parcels have a total weight of 22 Kgs. Parcel 1 is 4 times the weight of parcel 3. Parcel 4 is half the weight of parcel 2. If parcel 1 weighs 8 Kgs., how much does parcel 4 weigh.
I tried to work this out as follows and got stuck.
Parcel 1 = 8
parcel 2 = X
parcel 3 = 2
Parcel 4 = x/2
8+X+2+X/2 = 22
10+X+X/2 + 22
X+X/2 = 22-10
X+X/2=12
Found 2 solutions by richwmiller, MathTherapy:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Now combine them .
x+x/2=12
2/2x+1/2x=12
3/2x=12
or 1.5 x=12
or 1 1/2 x=12
x=8
x/2=4

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Hi,
Could you please help me solve the below problem. Much appreciate your help. Thank you very much for your time and help.
regards
Simsasha
Four parcels have a total weight of 22 Kgs. Parcel 1 is 4 times the weight of parcel 3. Parcel 4 is half the weight of parcel 2. If parcel 1 weighs 8 Kgs., how much does parcel 4 weigh.
I tried to work this out as follows and got stuck.
Parcel 1 = 8
parcel 2 = X
parcel 3 = 2
Parcel 4 = x/2
8+X+2+X/2 = 22
10+X+X/2 + 22
X+X/2 = 22-10
X+X/2=12


Let weight of parcel 4, be F

Then weight of parcel 2 is: 2F

Weight of parcel 1:         8 kg

Weight of parcel 3:         1%2F4 of parcel 1, or 1%2F4 of 8, or 2 kg



Altogether they weigh 22 kg, so we can say that:

F + 2F + 8 + 2 = 22

3F + 10 = 22

3F = 22 - 10 

F, or weight of parcel 4 is: 12%2F3, or highlight_green%284%29 kg

You can do the check!! 



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