SOLUTION: (3^2 - 2^2)^3 + 42 ÷ 6 x 3^2 - 9 (9-4)^3 + 42 / 6 x 9 - 9 125 + 42 / 54 - 9 125 + 0.77777777777777777778 - 9 116.7777777777777 The problem is that the answer is suppose to b

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: (3^2 - 2^2)^3 + 42 ÷ 6 x 3^2 - 9 (9-4)^3 + 42 / 6 x 9 - 9 125 + 42 / 54 - 9 125 + 0.77777777777777777778 - 9 116.7777777777777 The problem is that the answer is suppose to b      Log On


   

Question 759128: (3^2 - 2^2)^3 + 42 ÷ 6 x 3^2 - 9
(9-4)^3 + 42 / 6 x 9 - 9
125 + 42 / 54 - 9
125 + 0.77777777777777777778 - 9
116.7777777777777
The problem is that the answer is suppose to be 179 and I am following PEMDAS and I do not reach that answer
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
(3^2 - 2^2)^3 + 42 ÷ 6 x 3^2 - 9
= (9 - 4)^3 + 7 x 9 - 9
= 125 + 63 - 9
= 179
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(3^2 - 2^2)^3 + 42 ÷ 6 x 3^2 - 9
(9-4)^3 + 42 / 6 x 9 - 9
125 + 42 / 54 - 9 ************* ************
125 + 0.77777777777777777778 - 9
116.7777777777777