SOLUTION: how do i solve 1.1+lnx^2=6
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Question 740369
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how do i solve
1.1+lnx^2=6
Answer by
tommyt3rd(5050)
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1.1+lnx^2=6
1.1-1.1+lnx^2=6-1.1
lnx^2 = 4.9
e^lnx^2 = e^4.9
x^2=e^4.9
or
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