Question 590636: the probability of selecting a blue marble from the first bag is 1/8.the probability of selecting a blur tile from the second bag is 1/6. If one marble is selected from each bag what is the probability of selecting a blue marble from the first bag then selecting a marble other than blue from the second bag.
I need help I tried to multiply,add and i can't get that answer
Answer by ExplanationCentral(10)   (Show Source):
You can put this solution on YOUR website! The probability of the first event, selecting a blue marble from bag 1 is 1/8.
The probability of the second event, selecting a non blue marble from bag 2 is 5/6.
So assuming the two events are independent, the probability of the first event and then the second event occurring is (1/8)*(5/6) = 5/48.
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