SOLUTION: An official doubles tennis court has a length of 78' and a width of 36'. How many times greater is the length than the width of the court to the nearest tenth?

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Question 548239: An official doubles tennis court has a length of 78' and a width of 36'. How many times greater is the length than the width of the court to the nearest tenth?
Answer by solver91311(24713) About Me  (Show Source):
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Divide 78 by 36 and round to the nearest 10th.

John

My calculator said it, I believe it, that settles it
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