SOLUTION: If f(x) = 2x^2 + 6x - 5, then [f(x + h) - f(x)]/h = a. 6x + 3h - 4 b. 4x + 2h - 3 c. 10x + 5h + 2 d. 10x + 5h - 3 e. 8x + 4h + 5 f. 4x + 2h + 6 g. none of these

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: If f(x) = 2x^2 + 6x - 5, then [f(x + h) - f(x)]/h = a. 6x + 3h - 4 b. 4x + 2h - 3 c. 10x + 5h + 2 d. 10x + 5h - 3 e. 8x + 4h + 5 f. 4x + 2h + 6 g. none of these      Log On


   

Question 51182: If f(x) = 2x^2 + 6x - 5, then
[f(x + h) - f(x)]/h =
a. 6x + 3h - 4
b. 4x + 2h - 3
c. 10x + 5h + 2
d. 10x + 5h - 3
e. 8x + 4h + 5
f. 4x + 2h + 6
g. none of these
Answer by THANApHD(104) About Me  (Show Source):
You can put this solution on YOUR website!
2x^2 + 6x - 5

[f(x+h)-f(x)]/h
=[2(x+h)^2 + 6(x+h)-5]- [2x^2 + 6x - 5]/h
= (2x^2+4xh+2h^2 + 6x+6h - 5 - 2x^2 - 6x +5)/h
= 2h^2+4xh+6h/h
= h(2h + 4x+6)/h
= 2h+4x+6