Question 50486: (y+2) (y-3)=6
3a^2=14a+5
x(a-3)-y(3-a)
22z-9z^2-z3
a^4+a^3-72a^2
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! y+2) (y-3)=6
y^2-y-6=6
y^2-y-12=0
(y-4)(y+3)=0
y=4 or y=-3
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3a^2=14a+5
3a^2-14a-5=0
3a^2-15a+a-5=0
3a(a-5)+(a-5)=0
(a-5)(3a+1)=0
a=5 or a=-1/3
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x(a-3)-y(3-a)
=x(a-3)+y(a-3)
=(a-3)(x+y)
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22z-9z^2-z^3
=-z(z^2+9z-22)
=-z(z+11)(z-2)
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a^4+a^3-72a^2
=a^2(a^2+a-72)
=a^2(a+9)(a-8)
Cheers,
Stan H.
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