SOLUTION: [[4x+6]/[2x+8]] how would you simplify a fraction like this or like [8r^2-8r] / [2r-2]
i dont know if it would be right to simplify but changing [for the first equation] 6 to 3 an
Question 473358: [[4x+6]/[2x+8]] how would you simplify a fraction like this or like [8r^2-8r] / [2r-2]
i dont know if it would be right to simplify but changing [for the first equation] 6 to 3 and 8 to 2 VERY confused
Thank you!! Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! [[4x+6]/[2x+8]] how would you simplify a fraction like this
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You need to factor the numerator and the denominator:
[2(2x+3)]/[2(x+4)]
Then cancel any factor that is common to the numerator and the denominator:
= (2x+3)/(x+4)
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[8r^2-8r] / [2r-2]
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[8r(r^2-1)] / [2(r-1)]
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= [8r(r-1)(r+1)]/[2(r-1)]
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Cancel the common 2 and the common r-1 factors to get:
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= [4r(r+1)]
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Cheers,
Stan H.
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