SOLUTION: The sum of three consecutive even numbers is 138. what is the greatest number 52 50 48 46 44

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Question 4517: The sum of three consecutive even numbers is 138. what is the greatest number
52
50
48
46
44
Found 5 solutions by xcentaur, JimMarshall, Robee16, josgarithmetic, ikleyn:
Answer by xcentaur(357)   (Show Source):
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let the first number be x
then second number=(x+2)
then third number= ((x+2)+2)=(x+4)
then sum of all three numbers=x+(x+2)+(x+4)=138

3x+6=138
3x=132
x=132/3
x=44

Then largest number is equal to (x+4) = 48

ANS:48

Answer by JimMarshall(82)   (Show Source):
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et the first number be x
then second number=(x+2)
then third number= ((x+2)+2)=(x+4)
then sum of all three numbers=x+(x+2)+(x+4)=138

3x+6=138
3x=132
x=132/3
x=44

Then largest number is equal to (x+4) = 48 Ans

Answer by Robee16(18)   (Show Source):
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>> x + (x+2) + ((x+2)+2) = 138
>> x + (x+2) + (x+4) = 138
>> x + x + 2 + x + 4 = 138
>> 3x + 6 = 138
>> 3x = 138 - 6
>> 3x = 132

>> =

>> x = 44
>> (44) + (44+2) + ((44+2)+2) = 138
>> 44 + 46 + 48 = 138
>> 48 is the greatest number

Answer by josgarithmetic(39617)   (Show Source):
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Three consecutive even numbers:

-------the MIDDLE number, so the greatest number is 48.

Answer by ikleyn(52778)   (Show Source):
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.

If and when you are given the sum of three consecutive even integers - KNOW and REMEMBER that the middle number is one third ( ) of the sum. In this case, the middle number of the three consecutive even integers is = 46, so the greatest of them is 48. ANSWER

Solved.

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This problem was specially invented and designed for you in order you learned this simple truth.

(n-2) + n + (n+2) = 138 ====> 3n = 138 ===> n = = 46 ====> n+2 = 46 + 2 = 48.