SOLUTION: Please help me with this Math question: sqrt150 - sqrt24 -sqrt54 Sorry I don't remember how to do the sign for square root on the computer. Thank you!!!

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: Please help me with this Math question: sqrt150 - sqrt24 -sqrt54 Sorry I don't remember how to do the sign for square root on the computer. Thank you!!!       Log On


   



Question 346670: Please help me with this Math question:
sqrt150 - sqrt24 -sqrt54
Sorry I don't remember how to do the sign for square root on the computer.
Thank you!!!

Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
I don't think you are supposed to use a computer or calculator, even if you remember how to use them to find square roots. All computers or calculators can do with most square roots is to find a decimal approximation for the square root.

Instead, I believe your problem is to simplify the expression. Simplifying square roots involves finding perfect square factors of the radicand, if any. ("Radicand" is the name for the expression inside a radical (like a square root).) So we will start by looking for perfect square factors in each of the radicands and, if we find them, rewriting the radicands as a product involving these perfect squares:
sqrt%28150%29+-+sqrt%2824%29+-sqrt%2854%29
sqrt%2825%2A6%29+-+sqrt%284%2A6%29+-+sqrt%289%2A6%29
Next we use a property of radicals, sqrt%28a%2Ab%29+=+sqrt%28a%29%2Asqrt%28b%29, to separate the perfect squares factors into their own square roots:
sqrt%2825%29%2Asqrt%286%29+-+sqrt%284%29%2Asqrt%286%29+-+sqrt%289%29%2Asqrt%286%29
Now we can replace the square roots of the perfect squares:
5sqrt%286%29+-+2sqrt%286%29+-+3sqrt%286%29
Now the square roots have been simplified. Next we simplify the expression as a whole, if possible. It turns out that these are like terms so they can be added/subtracted. (If you have trouble seeing this, perhaps using a temporary variable will help. Let q+=+sqrt%286%29. Then the expression becomes: 5q+-+2q+-3q. This, I hope you can see, is an expression of like terms. And so is the expression with the square roots of 6!)

As it turns out, subtracting 2sqrt%286%29 from 5sqrt%286%29 leaves 3sqrt%286%29 (just like 5q - 2q = 3q). And if we then subtract 3sqrt%286%29 from 3sqrt%286%29 we get 0.

So the simplified expression is zero!