SOLUTION: (3x-2)^3=9x^2-6. Did I do this problem right? I just want to make sure before I hand it in. If not, could you show me what I did wrong? Thank you.

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: (3x-2)^3=9x^2-6. Did I do this problem right? I just want to make sure before I hand it in. If not, could you show me what I did wrong? Thank you.       Log On


   

Question 34066: (3x-2)^3=9x^2-6. Did I do this problem right? I just want to make sure before I hand it in. If not, could you show me what I did wrong? Thank you.
Answer by fanism(39) About Me  (Show Source):
You can put this solution on YOUR website!
you cannot simply cube each number seperatly...
(3x-2)^3
= (3x-2)(3x-2)(3x-2)
= (9x^2 - 12x + 4)(3x-2)
= 27x^3 - 54x^2 + 36x - 8