SOLUTION: ONE OF THE TWO NUMBERS EXCEEDS THE OTHER BY SEVEN AND IF WE ADD FOUR TIMES THE SMALLER TO FIVE TIMES THE GREATER WE GET 143.FIND THE NUMBERS?

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: ONE OF THE TWO NUMBERS EXCEEDS THE OTHER BY SEVEN AND IF WE ADD FOUR TIMES THE SMALLER TO FIVE TIMES THE GREATER WE GET 143.FIND THE NUMBERS?      Log On


   

Question 319073: ONE OF THE TWO NUMBERS EXCEEDS THE OTHER BY SEVEN AND IF WE ADD FOUR TIMES THE SMALLER TO FIVE TIMES THE GREATER WE GET 143.FIND THE NUMBERS?
Answer by unlockmath(1688) About Me  (Show Source):
You can put this solution on YOUR website!
Hello,
Let's have x be the smaller and (x+7) be the larger number. Here's the equation that can be setup:
4x+5(x+7)=143
Combine like terms to get:
9x+35=143
Subtract 35 from both sides to get:
9x=108
Divide by 9 to result in:
x=12
So the numbers are:
12 & 19
Make sense?
RJ
www.math-unlock.com