Question 268579: how do i add 6n/n+3 + n-1/n^2+5n+6?
Answer by persian52(161)   (Show Source):
You can put this solution on YOUR website! (6n)/(n)+3+n-(1)/(n^(2))+5n+6
Remove the common factors that were cancelled out.
6+3+n-(1)/(n^(2))+5n+6
Add 3 to 6 to get 9.
9+n-(1)/(n^(2))+5n+6
Add 6 to 9 to get 15.
15+n-(1)/(n^(2))+5n
Since n and 5n are like terms, add 5n to n to get 6n.
15+6n-(1)/(n^(2))
To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is n^(2). Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions.
6n*(n^(2))/(n^(2))+15*(n^(2))/(n^(2))-(1)/(n^(2))
Complete the multiplication to produce a denominator of n^(2) in each expression.
(6n^(3))/(n^(2))+(15n^(2))/(n^(2))-(1)/(n^(2))
Combine the numerators of all expressions that have common denominators.
(6n^(3)+15n^(2)-1)/(n^(2))
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