SOLUTION: (-3y^2+3y+8)/((y-3)(3y+1))=-(〖3y〗^2-3y-8)/((y-3)(3y+1)) is correct?

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: (-3y^2+3y+8)/((y-3)(3y+1))=-(〖3y〗^2-3y-8)/((y-3)(3y+1)) is correct?      Log On


   

Question 255103: (-3y^2+3y+8)/((y-3)(3y+1))=-(〖3y〗^2-3y-8)/((y-3)(3y+1)) is correct?
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
No the 3 does not get squared.