SOLUTION: (b2-c2)a+(c2-a2)b+(a2-b2)c

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Question 252968: (b2-c2)a+(c2-a2)b+(a2-b2)c
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
This was under fractions, but i don't see any. Let's assume the original question appears to be:
%28b%5E2-c%5E2%29%2Fa%2B%28c%5E2-a%5E2%29%2Fb%2B%28a%5E2-b%5E2%29%2Fc
we can factor all of the differences of squares as
%28b-c%29%28b%2Bc%29%2Fa+%2B+%28c-a%29%28c%2Ba%29%2Fb+%2B+%28a-b%29%28a%2Bb%29%2Fc
we need common denominator of abc. we get
%28bc%28b%2Bc%29%28b-c%29+%2Bac%28a%2Bc%29%28a-c%29+%2B+ab%28a%2Bb%29%28a-b%29%29 / abc
At this point I don't see any further steps.