SOLUTION: 2zx2y=18 where x=1,z=y

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Question 206976: 2zx2y=18 where x=1,z=y
Answer by RAY100(1637) About Me  (Show Source):
You can put this solution on YOUR website!
2zx2y=18,,,but z=y,,,x=1,
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2(y)(1)2y=18
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4y^2 =18
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y^2 =18/4 =4.5
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y= +/-2.12
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