SOLUTION: I'm trying to find for what x and y value that this inequality is true: ln x - ln y < (x^2-y^2)/2xy I've simplified it to ln (x - y) < (x^2-y^2)/2xy I can't remember where

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: I'm trying to find for what x and y value that this inequality is true: ln x - ln y < (x^2-y^2)/2xy I've simplified it to ln (x - y) < (x^2-y^2)/2xy I can't remember where      Log On


   

Question 18431: I'm trying to find for what x and y value that this inequality is true:
ln x - ln y < (x^2-y^2)/2xy
I've simplified it to ln (x - y) < (x^2-y^2)/2xy
I can't remember where to go from here. I'm hoping you can point me in the right direction!
Thanks!
Answer by kelljohn19(2) About Me  (Show Source):
You can put this solution on YOUR website!
(x - y) < (x^2-y^2)/2xy