SOLUTION: Use properties of equality to isolate x on one side of the equation and the small figures on the other side. The problem: If x/5-2=x/3, evaluate x squared -2. x/5 is x over 5 an

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: Use properties of equality to isolate x on one side of the equation and the small figures on the other side. The problem: If x/5-2=x/3, evaluate x squared -2. x/5 is x over 5 an      Log On


   

Question 177240This question is from textbook
: Use properties of equality to isolate x on one side of the equation and the small figures on the other side.
The problem: If x/5-2=x/3, evaluate x squared -2. x/5 is x over 5 and x/3 is x over 3. I have no idea. Please help! This question is from textbook

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
First, solve for "x":

x%2F5-2=x%2F3 Start with the given equation.


15%28x%2Fcross%285%29%29-15%282%29=15%28x%2Fcross%283%29%29 Multiply EVERY term by the LCD 15 to clear the fractions.


3x-30=5x Distribute and multiply.


3x=5x%2B30 Add 30 to both sides.


3x-5x=30 Subtract 5x from both sides.


-2x=30 Combine like terms on the left side.


x=%2830%29%2F%28-2%29 Divide both sides by -2 to isolate x.


x=-15 Reduce.


Now that we found "x", we can evaluate x%5E2-2


x%5E2-2 Start with the given expression.


%28-15%29%5E2-2 Plug in x=-15


225-2 Square -15 to get 225


223 Subtract


So x%5E2-2=223 when x=-15