SOLUTION: The average number of boys in 1A, 1B and 1C is 18. This is 4 more than the average number of girls in the 3 rooms. 2/7 of the total number of girls are in 1C. 3/2 of the number of

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: The average number of boys in 1A, 1B and 1C is 18. This is 4 more than the average number of girls in the 3 rooms. 2/7 of the total number of girls are in 1C. 3/2 of the number of       Log On


   



Question 1191538: The average number of boys in 1A, 1B and 1C is 18. This is 4 more than the average number of girls in the 3 rooms. 2/7 of the total number of girls are in 1C. 3/2 of the number of girls in 1B is the same as 3/7 of the total number of girls in the 3 rooms. What fraction of the total number of boys in the 3 rooms is in 1A if there are 40 pupils in 1A?
Answer by ikleyn(52779) About Me  (Show Source):
You can put this solution on YOUR website!
.
The average number of boys in 1A, 1B and 1C is 18.
This is 4 more than the average number of girls in the 3 rooms.
2/7 of the total number of girls are in 1C.
3/2 of the number of girls in 1B is the same as 3/7 of the total number of girls in the 3 rooms.
What fraction of the total number of boys in the 3 rooms is in 1A if there are 40 pupils in 1A?
~~~~~~~~~~~~~


            I will recover all needed and required consequences from the condition, step by step.


(1)  The average of girls in the 3 rooms is 18-4 = 14.


(2)  Hence, the total girls in the 3 rooms is 14*3 = 42.


(3)  The number of girls in 1C is 2/7 of 42,  i.e.  12 girls.


(4)  3/7 of the total numer of girls in the 3 rooms is 3/7 of 42, or 18.


(5)  3/2 of the number of girls in 1B is 18;

     hence, the number of girls in 1B is 2/3 of 18, i.e. 12.


(6)  It implies that the number of girls in 1A is 42-12-12 = 18.


(7)  Since there are 40 pupils in 1A, the number of boys in 1A is 40-18 = 22.


(8)  The total number of boys in all three classes is 18*3 = 54.


(9)  Hence, the ratio of boys in 1A to the total boys is  22%2F54 = 11%2F27.    ANSWER

Solved.