SOLUTION: Josef had a copper wire from which he cut 2 pieces. The first piece was 1.025m long and the second was 0.08 m shorter. After cutting the second piece, 2.5 m of copper wire were lef

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: Josef had a copper wire from which he cut 2 pieces. The first piece was 1.025m long and the second was 0.08 m shorter. After cutting the second piece, 2.5 m of copper wire were lef      Log On


   

Question 1168337: Josef had a copper wire from which he cut 2 pieces. The first piece was 1.025m long and the second was 0.08 m shorter. After cutting the second piece, 2.5 m of copper wire were left in the coil.What is the original length of the coil of wire?
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
first was 1.025 m and second was 1.017 m. That is 2.042 m.
There is 2.5 m left, so the original length is 2.042+2.5=4.542 m