SOLUTION: Two customers entered kim's bakery at the same time. One of them bought 7 bagels and 5 doughnuts and paid $7.35. The other customer bought 4 bagels and 5 doughnuts and paid $ 6.40.

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: Two customers entered kim's bakery at the same time. One of them bought 7 bagels and 5 doughnuts and paid $7.35. The other customer bought 4 bagels and 5 doughnuts and paid $ 6.40.      Log On


   

Question 1137776: Two customers entered kim's bakery at the same time. One of them bought 7 bagels and 5 doughnuts and paid $7.35. The other customer bought 4 bagels and 5 doughnuts and paid $ 6.40. What is the price of each bagel and each doughnut?
Found 2 solutions by greenestamps, josgarithmetic:
Answer by greenestamps(13198) About Me  (Show Source):
You can put this solution on YOUR website!


The difference between the two purchases is 3 more bagels by the first customer, whose cost was $0.95 more.

That makes the cost of each bagel a number that is not a whole number; so at this point I conclude that the problem as you present it is faulty.

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
b bagels
d doughnuts

system%287b%2B5d=7.35%2C4b%2B5d=6.4%29

E%5B1%5D-E%5B2%5D
3b=0.95
b=0.3166666667......
OR 31%262%2F3centsperbagel
Too strange a price value