SOLUTION: There are two triples of positive integers (a,b,c and d,e,f) such that a²+b²+c²=86 and d²+e²+f²=86. Evaluate the expression absolute value of abc-def.

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: There are two triples of positive integers (a,b,c and d,e,f) such that a²+b²+c²=86 and d²+e²+f²=86. Evaluate the expression absolute value of abc-def.       Log On


   

Question 1106473: There are two triples of positive integers (a,b,c and d,e,f) such that
a²+b²+c²=86 and d²+e²+f²=86. Evaluate the expression absolute value of
abc-def.
Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
There are two triples of positive integers (a,b,c and d,e,f) such that
a²+b²+c²=86 and d²+e²+f²=86. Evaluate the expression absolute value of
------------------
Obviously, all are less than 10.
There's no algebraic solution, just trial and error.
There's no reason for me to do it.
You do it.

Answer by ikleyn(52777) About Me  (Show Source):
You can put this solution on YOUR website!
.
1)  86 = 1^2 + 2^2 + 9^2


2)  86 = 5^2 + 5^2 + 6^2.


You do the rest.