Question 1101010: The term that succeed 1000 in the series 13,26,39........is?
Answer by KMST(5328)   (Show Source):
You can put this solution on YOUR website! The word "succeeds" in the wording of the question puzzles me.
I do not know what was meant by that.
When we are given the first few terms of a sequence,
we have to guess what is the idea of the person designing the sequence.
We expect it to be a popular choice, one that most math teachers and students would expect.
13,26,39........is expected to be an arithmetic sequence
where each term is the previous term plus 13.
They are all multiples of 13,
so 1000 is not a term of that sequence,
but 1001=77*13 is the 77th term, and the first term exceeding 1000.
The 1000th term is  .
UNCOMMON DESIGNS FOR THE REMAINDER OF THAT SEQUENCE:
13,26,39,412,515,618,721,824,927,1030,1133,...
Maybe the person designing that problem has a good imagination.
13,26,39,4=,5e,6y,7o,8],...
|
|
|
