Question 1050512: The height of an object off the ground, h (in feet) t seconds after it is launched into the air is given by
h(t) = −16t2 + 128t, 0 ≤ t ≤ 8.
Find the average rate of change of h over the interval
[4, 8].
_______ feet per second
Interpret your result.
During the last four seconds of the objects's time in the air, it is falling at a average rate of _______
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! The height of an object off the ground, h (in feet) t seconds after it is launched into the air is given by
h(t) = −16t2 + 128t, 0 ≤ t ≤ 8.
Find the average rate of change of h over the interval
[4, 8].
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Find h(8)
Subtract h(4)
Divide by 4.
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