SOLUTION: find an equation to a line perpendicular to x-3 through (-2,5)

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Question 218374: find an equation to a line perpendicular to x-3 through (-2,5)
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
To be perpendicular, the slope of the second line must be the negative reciprocal of the first line.
The slope of the first line is 1 y+=+mx+%2B+b and the line is y+=+1x+-3
SO the second line is in the form y+=+-1x%2Bb
You are given a point on the line as (-2,5)
5+=+-1%2A%28-2%29+%2Bb
5+=+2+%2Bb
3+=+b
So the line is y+=+-x%2B3
graph%28400%2C400%2C+-10%2C10%2C-10%2C10%2Cx-3%2C+-x%2B3%29