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This Lesson (Solving system of linear equation in 19 unknowns) was created by by ikleyn(52778)  : View Source, ShowAbout ikleyn:
Solving system of linear equation in 19 unknowns
You can consider this problem as a Math joke, or as a Math entertainment, or seriously.
In any case, my goal is to teach you.
Problem 1If , , . . ., satisfy
= 1,
= 2,
= 3,
. . . . . . . . .
= 16,
= 17,
= 18,
= 19,
find the value of .
Solution
Let's write the system of equations in full
= 1 (1)
= 2 (2)
= 3 (3)
. . . . . . . . .
= 16 (16)
= 17 (17)
= 18 (18)
= 19 (19)
Subtract equation (1) from equation (2):
- = 2 - 1
= 1
= + 1
Subtract equation (2) from equation (3):
- = 3 - 2
- = 1
= + 1
In general, we have = .
This means:
= + 1
= =
= =
= =
Similarly,
=
= =
=
= =
also,
=
= =
= =
= =
and
=
= =
= =
Now let's use equations (1), (17), (18), and (19).
From equation (1), = 1 (20)
From equation (17), = 17 (21)
From equation (18), = 18 (22)
From equation (19), = 19 (23)
Substituting the expressions we find:
from (20): = 17
= 17
= 5 (17')
from (21): = 18
= 18
= 10 (18')
from (22): = 19
= 19
= 15 (19')
Add equations (17'), (18') and (19'). You will get
= 5 + 10 + 15
= 30.
Divide both sides by 4
= 7.5. (24)
Now we are on the finish line.
From equation (17') subtract equation (24). You will get = 5 - 7.5 = -2.5.
From equation (18') subtract equation (24). You will get = 10 - 7.5 = 2.5.
From equation (19') subtract equation (24). You will get = 15 - 7.5 = 7.5.
From equation (23), = 19 - - - = 19 - 0 - (-2.5) - 2.5 - 7.5 = 11.5
For completeness, let's determine a-1 from the very first equation in this post
= = 1 - ((-2.5) + 2.5 + 7.5) = 1 - 7.5 = -6.5.
From this point, all 19 terms , , , , , . . . , can be determined.
See this table below
a_1 a_2 a_3 a_4 a_5 a_6 a_7 a_8 a_9 a_10 a_11 a_12 a_13 a_14 a_15 a_16 a_17 a_18 a_19
-2.5 2.5 7.5 -6.5 -1.5 3.5 8.5 -5.5 -0.5 4.5 9.5 -4.5 0.5 5.5 10.5 5.5 1.5 6.5 11.5
You may check that all given 19 original equations are satisfied.
Final Answer: = 11.5.
My other lessons in this site on determinants of 3x3-matrices and the Cramer's rule for solving systems of linear equations in three unknowns are
- Determinant of a 3x3 matrix
- Co-factoring the determinant of a 3x3 matrix
- HOW TO solve system of linear equations in three unknowns using determinant (Cramer's rule)
- Solving systems of linear equations in three unknowns using determinant (Cramer's rule)
- Solving word problems by reducing to systems of linear equations in three unknowns
- The tricks to solve some word problems with three and more unknowns using mental math
- Solving systems of non-linear equations in three unknowns using Cramer's rule
- Sometime two equations are enough to find three unknowns by an UNIQUE way
- Two very different approaches to one word problem
- Solving word problems in three unknowns by the backward method
- Solving system of linear equation in 17 unknowns
- OVERVIEW of LESSONS on determinants of 3x3-matrices and Cramer's rule for systems in 3 unknowns
under the current topic Matrices, determinant, Cramer rule of the section Algebra-II.
My other lessons in this site on solving systems of linear equations in three unknowns are
- Solving systems of linear equations in 3 unknowns by the Substitution method,
- BRIEFLY on solving systems of linear equations in 3 unknowns by the Substitution method,
- Solving systems of linear equations in 3 unknowns by the Elimination method and
- BRIEFLY on solving systems of linear equations in 3 unknowns by the Elimination method
Use this file/link ALGEBRA-II - YOUR ONLINE TEXTBOOK to navigate over all topics and lessons of the online textbook ALGEBRA-II.
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