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Question 730644: Determinate
3y-z-4=0
Y+2z-13=0
2y-5z+11=0
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Determinate
3y-z-4=0
Y+2z-13=0
2y-5z+11=0
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z = 3y-4
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Substitute into the 2nd equation and solve for "y":
y + 2*(3y-4)-13 = 0
7y - 21 = 0
y = 3
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Therefore z = 3*3-4 = 5
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Checking:
2y-5z+11 = 0
6-25+11 = 0
8 = 0
False
Conclusion: The system of 3 equations is inconsistent
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Cheers,
Stan H.
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