SOLUTION: Last Monday at 7:30 a.m., an airline flew 89 passengers on a commuter flight from Boston to New York. Some of the passengers paid $120 for their tickets and the rest paid $230 for
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-> SOLUTION: Last Monday at 7:30 a.m., an airline flew 89 passengers on a commuter flight from Boston to New York. Some of the passengers paid $120 for their tickets and the rest paid $230 for
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Question 57158This question is from textbook
: Last Monday at 7:30 a.m., an airline flew 89 passengers on a commuter flight from Boston to New York. Some of the passengers paid $120 for their tickets and the rest paid $230 for their tickets. The total cost of all of the tickets was $14,200. How many passengers bought $120 tickets? How many bought $230 tickets? This question is from textbook
You can put this solution on YOUR website! To solve this question you must change the word problem to a linear equation.
This can be done by making the passengers that paid $120 for their ticket (X) and the passenger that paid $230 for their ticket (Y)
The total amount of passengers is;
X+Y=89
and the ticket cost per passenger can be represented by;
120X+230Y=14200
by multiplying the first equation by 120, you can solve the system for y. This is shown below.
(X+Y=89)x120
120X+120Y=10680
isolate Y from the 2 equations;
120X+120Y=10680
120X+230Y=14200
-110Y=-3520
Y=32
Substitute Y into the first equation to find X
X+Y=89
X+32=89
X=57
So 57 passengers paid $120 and 32 paid $230
