SOLUTION: {{{A=(matrix(2,2,2,-5,3,1))}}}
Evaluate the square of A and find x,y,z, not all zero, such that the matrix
xI+yA+zAA is the zero matrix.
Algebra ->
Matrices-and-determiminant
-> SOLUTION: {{{A=(matrix(2,2,2,-5,3,1))}}}
Evaluate the square of A and find x,y,z, not all zero, such that the matrix
xI+yA+zAA is the zero matrix.
Log On
We will find those three terms separately:
To find zAA we first find the square of A, which is AA
(That was the first thing asked for, the square of A)
Now we multiply that by z to get zAA:
Next we find their sum:
This must equal to the zero 2×2 matrix, so,
We form this system by setting each element = 0:
We solve that system by Gaussian elimination:
By using row operations we find the row reduced echelon form
of that augmented matrix.
The first two rows of that matrix gives us
the system:
or
To find all solutions, we choose a constant k for z, then
Edwin