SOLUTION: Find x1 and x2 for(show steps involved): [-4 5][x1]+[ 3]=[71] [-2-4][x2] [18] [ 0] *note* both lines are part of the same matrix equation, I didn't know how to type it as a

Algebra ->  Matrices-and-determiminant -> SOLUTION: Find x1 and x2 for(show steps involved): [-4 5][x1]+[ 3]=[71] [-2-4][x2] [18] [ 0] *note* both lines are part of the same matrix equation, I didn't know how to type it as a       Log On


   



Question 324812: Find x1 and x2 for(show steps involved):
[-4 5][x1]+[ 3]=[71]
[-2-4][x2] [18] [ 0]
*note* both lines are part of the same matrix equation, I didn't know how to type it as a continuous multi-line matrix bracket.

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
I think this is what you mean.

Simplify,

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[A][x]=[b]
[A]inv[A][x]=[A]inv[b]
[x]=[A]inv[b]
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[A]=%28matrix%282%2C2%2C-4%2C5%2C-2%2C-4%29%29
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Find the inverse of the coefficient matrix [A],
det([A])=26
[A]inv=%281%2F26%29%2A%28matrix%282%2C2%2C-4%2C-5%2C2%2C-4%29%29
[x]=%281%2F26%29%2A%28matrix%282%2C1%2C23%2C-44%29%29
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x1=23%2F26
x2=-44%2F26=-22%2F13