SOLUTION: I have to solve a 4X4 matrix
w x y z
2 -2 -2 2 10
1 1 1 1 -5
3 1 -1 4 -2
1 3 -2 2 -6
Now I know I can flip row 2 and row 1
1 1 1 1 -5
2 -2 -2 2 10
3 1
Algebra ->
Matrices-and-determiminant
-> SOLUTION: I have to solve a 4X4 matrix
w x y z
2 -2 -2 2 10
1 1 1 1 -5
3 1 -1 4 -2
1 3 -2 2 -6
Now I know I can flip row 2 and row 1
1 1 1 1 -5
2 -2 -2 2 10
3 1
Log On
Question 20162: I have to solve a 4X4 matrix
w x y z
2 -2 -2 2 10
1 1 1 1 -5
3 1 -1 4 -2
1 3 -2 2 -6
Now I know I can flip row 2 and row 1
1 1 1 1 -5
2 -2 -2 2 10
3 1 -1 4 -2
1 3 -2 2 -6
Now I can slove the second row by mutiplying row1 one by -2 and adding row2 etc.
1 1 1 1 -5
0 -4 -4 0 20
0 -2 -7 1 13
0 2 -3 1 -1
Now I am stuck where do I go from here????
You can put this solution on YOUR website! I will continue from where you left the problem....
1 1 1 1 -5
0 -4 -4 0 20
0 -2 -7 1 13
0 2 -3 1 -1
flip row 3 and row 2
1 1 1 1 -5
0 -2 -7 1 13
0 -4 -4 0 20
0 2 -3 1 -1
no multiply row 2 with 2 and subtract it from row 3
and simultaneously add row 2 to row 4
1 1 1 1 -5
0 -2 -7 1 13
0 0 10 -2 -6
0 0 -10 2 12
now add row 3 to row 4
1 1 1 1 -5
0 -2 -7 1 13
0 0 10 -2 -6
0 0 0 0 6
since the first 4 elements is fourth row are zeros and the last element is non zero, the system doesnot possess solution.
the system is inconsistent