SOLUTION: 2x-y+z=0 x+3y+2z=16 3x-y+z=3

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Question 1080680: 2x-y+z=0
x+3y+2z=16
3x-y+z=3
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Use Cramer's rule,
A=%28matrix%283%2C3%2C%0D%0A2%2C-1%2C1%2C%0D%0A1%2C3%2C2%2C%0D%0A3%2C-1%2C1%29%29
abs%28A%29=-5
.
.
A%5Bx%5D=%28matrix%283%2C3%2C%0D%0A0%2C-1%2C1%2C%0D%0A16%2C3%2C2%2C%0D%0A3%2C-1%2C1%29%29
abs%28A%5Bx%5D%29=-15
.
.
A%5By%5D=%28matrix%283%2C3%2C%0D%0A2%2C0%2C1%2C%0D%0A1%2C16%2C2%2C%0D%0A3%2C3%2C1%29%29
abs%28A%5By%5D%29=-25
.
.
A%5Bz%5D=%28matrix%283%2C3%2C%0D%0A2%2C-1%2C0%2C%0D%0A1%2C3%2C16%2C%0D%0A3%2C-1%2C3%29%29
abs%28A%5Bz%5D%29=5
.
.
.
.
x=abs%28A%5Bx%5D%29%2Fabs%28A%29=%28-15%29%2F%28-5%29=3
y=abs%28A%5By%5D%29%2Fabs%28A%29=%28-25%29%2F%28-5%29=5
z=abs%28A%5Bz%5D%29%2Fabs%28A%29=%285%29%2F%28-5%29=-1