Questions on Algebra: Linear Equations, Graphs, Slope answered by real tutors!

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Question 1199720: Describe the transformation for this problem. There may be more than one(max you can have with only changes to a and d are three).
Given f(x) = x, describe the transformation for g(x) = -4/5 • f(x).

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Question 1199725: Given f(x) = 3x - 1, and g(x) = -2 • f(x) - 1. Describe the transformations(list them) and write the new simplified equation for g(x)
(I am resubmitting this question because I accidentally entered the wrong information for the question. Please disregard the other similar question.)

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Question 1199780: You purchased 225 shares of stocks total. Stock a at 50 per share and stock b at 75 per share. For a total of 13,750. How many of each were purchased?
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Question 1199799: 2x-y=1
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Question 1199798: 3x-y=2
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Question 1199804: Using graphical method, please solve
4x^2-y^2=15
2x-y=5

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Question 1199808: Find the intercept and the slope for each of the following equations:
1. 10x+20y = 6
intercept=
slope=
2. 9x+14y = 10 (correct to 6 decimals)
intercept=
slope=

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Question 1199811: Solve the following systems graphically and algebraically.
-17x+18y = 89
-18x-11y = -26

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Question 1199810: Set up a system of simultaneous equations to solve the following problem:
(equations must be in standard form and must not contain any fractions or decimals)
1. Jenny and Lisa agreed to form a partnership. The partnership agreement requires that Lisa invest $2,751.00 more than three-fourths of what Jenny is to invest. If the partnership's capital is to be $51, 107.00, how much should Lisa invest?

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Question 1199806: Solve the following systems graphically and algebraically.
-13x-15y = -31
-7x+9y = 137

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Question 1199807: 6x-5y= -30
2x+2y = 12

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Question 1200166: how do I graph 2x-y=4
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Question 1200166: how do I graph 2x-y=4
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Question 1200181: Mark put last year's bonus of
$2,800 into two accounts. He
invested part in a CD with
2.2% annual interest and the
rest in a money market fund
with 2.9% annual interest. His
total interest for the year was
$67.20. How much did he invest in each account?

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Question 1200208: Two cars leave a location traveling in opposite directions. If one car averages 73 miles per hour and the other averages 77 miles per hour, then how long will it take for them to separate a distance of 510 miles?
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Question 1200209: Find the slope of the line (-2,2) and (4,-1)
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Question 1200209: Find the slope of the line (-2,2) and (4,-1)
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Question 1200209: Find the slope of the line (-2,2) and (4,-1)
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Question 1200209: Find the slope of the line (-2,2) and (4,-1)
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Question 1200210: Find the equation of the line (in slope intercept form) passing through the points (-2,1) and (3,2)
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Question 1200210: Find the equation of the line (in slope intercept form) passing through the points (-2,1) and (3,2)
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Question 1200219: a local dairy association enlists the help of a marketing research firm to predict the demand for milk. the research firm finds that the local demand for milk can be predicted by the equation g = -4,000p + 10,000, where p represents the price per quart (in dollars) and g represents the number of quarts purchased per week. (a) graph the equation. (b) identify the slope and q intercept.o oil (s , -) bris (8.6--) (c) interpret the meaning of the slope and g intercept in this application.
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Question 1200220: a local dairy association enlists the help of a marketing research firm to predict the demand for milk. the research firm finds that the local demand for milk can be predicted by the equation g = -4,000p + 10,000, where p represents the price per quart (in dollars) and g represents the number of quarts purchased per week. (a) graph the equation. (b) identify the slope and q intercept.o oil (s , -) bris (8.6--) (c) interpret the meaning of the slope and g intercept in this application.
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Question 1200241: solve the following systems using the elimination method. Write your complete solutions.
1. x - 2y = 5 and 2x + 3y = -32
2. 3x + 4y = 3 and 2x - 3y = 19
3. 3x + 5y = -14 and 2x - y = -18

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Question 1200254: Find the equation of the line through the point (5,0) and perpendicular to the line y=(4x/3)+5. Express the equation of the line in slope-intercept form, y=mx+b.
So I am assuming that I need to put the points (5,0) into the y=mx+b so I did that. 0=(4/3)(5/1)+b and solved.
0=(20/3)+b so then I solved again so is b=-(20/3)?
I don't know what part of this I am doing wrong but I want to make sure I understand the content. Any help is greatly appreciated :)

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Question 1200254: Find the equation of the line through the point (5,0) and perpendicular to the line y=(4x/3)+5. Express the equation of the line in slope-intercept form, y=mx+b.
So I am assuming that I need to put the points (5,0) into the y=mx+b so I did that. 0=(4/3)(5/1)+b and solved.
0=(20/3)+b so then I solved again so is b=-(20/3)?
I don't know what part of this I am doing wrong but I want to make sure I understand the content. Any help is greatly appreciated :)

Click here to see answer by ikleyn(52781) About Me 

Question 1200256: Find the equation of the line through the point (6,6) and parallel to the point y=6-(x/2). Express the equation of the line in slope-intercept form, y=mx+b.
My first step was to put the (6,6) into y=mx+b
6=-(1/2)(6)+b -> 6=-(6/2)+b -> b=(18/2)? so then y=-(1/2)x+(18/2)
If someone wouldn't mind going over the work I would greatly appreciate it :)

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Question 1200256: Find the equation of the line through the point (6,6) and parallel to the point y=6-(x/2). Express the equation of the line in slope-intercept form, y=mx+b.
My first step was to put the (6,6) into y=mx+b
6=-(1/2)(6)+b -> 6=-(6/2)+b -> b=(18/2)? so then y=-(1/2)x+(18/2)
If someone wouldn't mind going over the work I would greatly appreciate it :)

Click here to see answer by ikleyn(52781) About Me 
Question 1200256: Find the equation of the line through the point (6,6) and parallel to the point y=6-(x/2). Express the equation of the line in slope-intercept form, y=mx+b.
My first step was to put the (6,6) into y=mx+b
6=-(1/2)(6)+b -> 6=-(6/2)+b -> b=(18/2)? so then y=-(1/2)x+(18/2)
If someone wouldn't mind going over the work I would greatly appreciate it :)

Click here to see answer by math_tutor2020(3816) About Me 

Question 1200253: Find the value of K so that the two lines are perpendicular. Line one contains the points (-6,4) and (-2,5) and line two contains the points (-3,4) and (0,k).
I know I need to do y2-y1/x2-x1 so I did that for both of them and got (1/4) for the first line and (k-4/3) for the second line.
Here is where I need help because I don't know what to do next. Any and all help is greatly appreciated :)

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Question 1200253: Find the value of K so that the two lines are perpendicular. Line one contains the points (-6,4) and (-2,5) and line two contains the points (-3,4) and (0,k).
I know I need to do y2-y1/x2-x1 so I did that for both of them and got (1/4) for the first line and (k-4/3) for the second line.
Here is where I need help because I don't know what to do next. Any and all help is greatly appreciated :)

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Question 1200255: Find the equation of the line with a y-intercept of -2 and a slope of -(6/5). Express the equation of the line in slope-intercept form, y=mx+b.
So I know I need to put this into y=mx+b so
-2=-(6/5)(0)+b
Would this mean that b=-2? so then it would be y=-(6/5)x-2 as the answer?
Any help is greatly appreciated :)


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Question 1200271: Find the equation of the line through the points (-5,3) and (-6,-1). Express the equation of the line in slope=intercept form, y=mx+b.
So I know y2-y1/x2-x1 so I did that (-1-3/-6-(-5)=(-4/1)
y=mx+b so 3=-(4/1)(-5)+b
solved for that to get b=-17
y=(-4/1)x-17

Click here to see answer by josgarithmetic(39617) About Me 
Question 1200271: Find the equation of the line through the points (-5,3) and (-6,-1). Express the equation of the line in slope=intercept form, y=mx+b.
So I know y2-y1/x2-x1 so I did that (-1-3/-6-(-5)=(-4/1)
y=mx+b so 3=-(4/1)(-5)+b
solved for that to get b=-17
y=(-4/1)x-17

Click here to see answer by greenestamps(13200) About Me 
Question 1200271: Find the equation of the line through the points (-5,3) and (-6,-1). Express the equation of the line in slope=intercept form, y=mx+b.
So I know y2-y1/x2-x1 so I did that (-1-3/-6-(-5)=(-4/1)
y=mx+b so 3=-(4/1)(-5)+b
solved for that to get b=-17
y=(-4/1)x-17

Click here to see answer by math_tutor2020(3816) About Me 
Question 1200271: Find the equation of the line through the points (-5,3) and (-6,-1). Express the equation of the line in slope=intercept form, y=mx+b.
So I know y2-y1/x2-x1 so I did that (-1-3/-6-(-5)=(-4/1)
y=mx+b so 3=-(4/1)(-5)+b
solved for that to get b=-17
y=(-4/1)x-17

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Question 1200423: y=15x+3.5
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Question 1200483: Find the point of intersection of the lines:
2x+y=3
x-4y=6
I tried doing elimination to solve this and it said it was wrong (I'll put my work below)
2x+y=3
-2(x-4y=-12)
------------
9y=-9
y=-1
------
2x+y=3
2x-1=3
2x=4
x=2
------
So that would mean y is -1 and x is 2? (2,-1)

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Question 1200484: Find the point of intersection of the lines
3x+5y=-11
x-2y=11
----------
3x+5y=-11
-3(x-2y=11
----------
3x+5y=-11
-3x+6y=-33
----------
-y=22
x-2y=11
x-2(22)=11
x-44=11
x=55
Is the answer really (55,22)?

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Question 1200484: Find the point of intersection of the lines
3x+5y=-11
x-2y=11
----------
3x+5y=-11
-3(x-2y=11
----------
3x+5y=-11
-3x+6y=-33
----------
-y=22
x-2y=11
x-2(22)=11
x-44=11
x=55
Is the answer really (55,22)?

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Question 1200640: x+y=8

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Question 1200640: x+y=8

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Question 1200729: compute the slope of the line segment connecting the two points.interpret the meaning of the slope in each case? (-2,3),(1,-9)
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Question 1200768:
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Question 1200816: Change the equation 5x + 4y = -4 to slope-intercept form
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