SOLUTION: Find a line perpendicular to: 6x -4y = 13 + y

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Question 373909: Find a line perpendicular to: 6x -4y = 13 + y
Found 2 solutions by Fombitz, mananth:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
6x+-4y+=+13+%2B+y
-5y+=+-6x%2B13+
y=%286%2F5%29x-13%2F5
Perpendicular lines have slopes that are negative reciprocals,
m%5B1%5D%2Am%5B2%5D=-1
%286%2F5%29%2Am%5B2%5D=-1
m%5B2%5D=-5%2F6
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highlight%28y=-%285%2F6%29x%29
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graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C0%2C%286%2F5%29x-13%2F5%2C-%285%2F6%29x%29

Answer by mananth(16949) About Me  (Show Source):
You can put this solution on YOUR website!
6x -4y = 13 + y
6x-4y-y=13
6x-5y=13
-5y= -6x+13
/-5
y = -6x/5 -13/5
...
m= -6/5
..
perpendicular line will have negative reciprocal as slope = 5/6
equation will be y = (5/6)x
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m.ananth@hotmail.ca