SOLUTION: Crew a can assemble 2 cars in 5 days, and crew b can assemble 3 cars in 7 days. If both work together assemble 100cars, with crew b working 10 days longer than crew a , how many d

Algebra ->  Linear-equations -> SOLUTION: Crew a can assemble 2 cars in 5 days, and crew b can assemble 3 cars in 7 days. If both work together assemble 100cars, with crew b working 10 days longer than crew a , how many d      Log On


   

Question 1209297: Crew a can assemble 2 cars in 5 days, and crew b can assemble 3 cars in 7 days. If both work together assemble 100cars, with crew b working 10 days longer than crew a , how many days must crew be work?
Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
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Crew A can assemble 2 cars in 5 days, and crew B can assemble 3 cars in 7 days.
If both work together assemble 100cars, with crew B working 10 days longer than crew A,
how many days must crew highlight%28cross%28be%29%29 B work?
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The setup equation is

    10%2A%283%2F7%29 + d%2A%282%2F5%29 + d%2A%283%2F7%29 = 100


Here 2/5 cars per day is the rate of work for team A;

     3/7 cars per day is the rate of work for team B;

     d is the number of days for two teams to work together.


To solve, multiply all the terms by 35.  You will get

    10*3*5 + 2*7*d + 3*5*d = 3500.


Simplify and find "d"

    150 + 14d + 15d = 3500

             29d    = 3500 - 150 

             29d    =    3350

               d    =    3350/29 = 11515%2F29.


ANSWER.  Crew B should work 10 + 11515%2F29 = 12515%2F29  days.

Solved.