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Question 1192362: Find the equation of the line in standard form.
1.) a = -8 and b = 2
2.) a= 4 and b = 8
3.) m = 5 and b = -8
4.) m = 3 and (5, -2)
5.) (-1, 9) and (-4, 3)
Find the equation of the line in general form.
1.) m = 1/3 and (-4, -8)
2.) m = 2 and b = 5
3.) a= 12 and b = -9
4.) a= 3 and b = 6
5.) (5, 7) and (3, 2)
Answer by CPhill(1959)   (Show Source):
You can put this solution on YOUR website! **1. Find the equation of the line in standard form.**
* **1.) a = -8 and b = 2**
* Slope-intercept form: y = mx + b
* y = -8x + 2
* Standard form: 8x + y = 2
* **2.) a = 4 and b = 8**
* Slope-intercept form: y = mx + b
* y = 4x + 8
* Standard form: 4x - y = -8
* **3.) m = 5 and b = -8**
* Slope-intercept form: y = mx + b
* y = 5x - 8
* Standard form: 5x - y = 8
* **4.) m = 3 and (5, -2)**
* Find b: -2 = 3(5) + b
* b = -2 - 15
* b = -17
* Slope-intercept form: y = 3x - 17
* Standard form: 3x - y = 17
* **5.) (-1, 9) and (-4, 3)**
* Find slope (m): (y2 - y1) / (x2 - x1) = (3 - 9) / (-4 - (-1)) = -6 / -3 = 2
* Find b: 9 = 2(-1) + b
* b = 11
* Slope-intercept form: y = 2x + 11
* Standard form: 2x - y = -11
**2. Find the equation of the line in general form.**
* **1.) m = 1/3 and (-4, -8)**
* Find b: -8 = (1/3)(-4) + b
* b = -8 + 4/3
* b = -20/3
* Slope-intercept form: y = (1/3)x - 20/3
* Standard form: x - 3y = 20
* **2.) m = 2 and b = 5**
* Slope-intercept form: y = 2x + 5
* Standard form: 2x - y = -5
* **3.) a = 12 and b = -9**
* Slope-intercept form: y = mx + b
* y = 12x - 9
* Standard form: 12x - y = 9
* **4.) a = 3 and b = 6**
* Slope-intercept form: y = mx + b
* y = 3x + 6
* Standard form: 3x - y = -6
* **5.) (5, 7) and (3, 2)**
* Find slope (m): (y2 - y1) / (x2 - x1) = (2 - 7) / (3 - 5) = -5 / -2 = 5/2
* Find b: 7 = (5/2)(5) + b
* b = 7 - 25/2
* b = -11/2
* Slope-intercept form: y = (5/2)x - 11/2
* Standard form: 5x - 2y = 11
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