SOLUTION: Given 5x+2y-6=0 write equation of a line that is perpendicular going through point (0,-3).

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Question 998337: Given 5x+2y-6=0 write equation of a line that is perpendicular going through point (0,-3).
Found 2 solutions by fractalier, stanbon:
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
Find the slope of this line first.
5x + 2y - 6 = 0
2y = -5x + 6
y = (-5/2)x + 3
This time you need a slope of 2/5 (it's the negative reciprocal)...
So using the point and y = mx + b, we get
-3 = (2/5)(0) + b
and b = -3
so your line is
y = (2/5)x - 3

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Given 5x+2y-6=0 write equation of a line that is perpendicular going through point (0,-3).
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Slope of the given line::
y = (-5/2)x + 3
slope = -5/2
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Slope of the perpendicular line:: 2/5
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Form of the answer::
y = mx + b
y = (2/5)x -3
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Cheers,
Stan H.
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