Question 986098: determine the equation of the straight line through the points (-2,1) and (3,-2)
Found 2 solutions by Timnewman, Alan3354:
Answer by Timnewman(323)   (Show Source):
You can put this solution on YOUR website! Hi dear,
if the straight line passes through the points (-2,1) and (3,-2)
Then,the formula below will be used to solve for the equation of the line.
where y1=1,y2=-2,x1=-2,x2=3.
substitute the above in the given formula
Therefore,
(y-1)(3+2)=(x+2)(-2-1)
5(y-1)=-3(x+2)
5y-5=3x+6
5y=3x+11
Answer by Alan3354(69443)  (Show Source):
You can put this solution on YOUR website! determine the equation of the straight line through the points (-2,1) and (3,-2)
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Step 1m find the slope
Slope m = diffy.diffx = (-2-1)/(3- -2) = -3/5
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Then use y-y1 = m*(x-x1) where (x1,y1) is either point.
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y-1 = (-3/5)*(x+2)
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