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Question 976506: What is the equation of a line that passes through (-2,-1) and (-4, -3)
Found 2 solutions by lwsshak3, stanbon:
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! What is the equation of a line that passes through (-2,-1) and (-4, -3)
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slope intercept form of equation for a line: y=mx+b, m=slope, b=y-intercept
For given problem:
m=∆y/∆x=(-3-(-1))/(-4-(-2)=-2/-2=1
equation: y=1x+b
using coordinates (-2, -1) on the line
b=y-x=-1+2=1
equation: y=x+1
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! What is the equation of a line that passes through (-2,-1) and (-4, -3)
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slope = (-3--1)/(-4--2) = -2/-2 = 1
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Form:: y = mx + b
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Solve for "b":
-1 = 1(-2) + b
b = 1
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Equation:
y = x + 1
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Cheers,
Stan H.
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