SOLUTION: a circle has an equation of 2(x-2)^2+2y^2=2. Find the center (h,k) and radius r and graph the circle. Find the intercepts if any,of the graph.
Algebra ->
Linear-equations
-> SOLUTION: a circle has an equation of 2(x-2)^2+2y^2=2. Find the center (h,k) and radius r and graph the circle. Find the intercepts if any,of the graph.
Log On
Question 960663: a circle has an equation of 2(x-2)^2+2y^2=2. Find the center (h,k) and radius r and graph the circle. Find the intercepts if any,of the graph. Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! a circle has an equation of 2(x-2)^2+2y^2=2. Find the center (h,k) and radius r and graph the circle. Find the intercepts if any,of the graph.
***
2(x-2)^2+2y^2=2
(x-2)^2+y^2=1
center:(2,0)
radius=1
x-intercepts
set y=0
(x-2)^2=1
x-2=±√1=±1
x=2±1
x=3, 1
y-intercepts: none
(