SOLUTION: How would you graph the equation y=2x+3?

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Question 960071: How would you graph the equation y=2x+3?

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

Solved by pluggable solver: Graphing Linear Equations
In order to graph y=2%2Ax%2B3 we only need to plug in two points to draw the line

So lets plug in some points

Plug in x=-6

y=2%2A%28-6%29%2B3

y=-12%2B3 Multiply

y=-9 Add

So here's one point (-6,-9)




Now lets find another point

Plug in x=-5

y=2%2A%28-5%29%2B3

y=-10%2B3 Multiply

y=-7 Add

So here's another point (-5,-7). Add this to our graph





Now draw a line through these points

So this is the graph of y=2%2Ax%2B3 through the points (-6,-9) and (-5,-7)


So from the graph we can see that the slope is 2%2F1 (which tells us that in order to go from point to point we have to start at one point and go up 2 units and to the right 1 units to get to the next point) the y-intercept is (0,3)and the x-intercept is (-1.5,0) ,or (-3%2F2,0)


We could graph this equation another way. Since b=3 this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,3).


So we have one point (0,3)





Now since the slope is 2%2F1, this means that in order to go from point to point we can use the slope to do so. So starting at (0,3), we can go up 2 units



and to the right 1 units to get to our next point


Now draw a line through those points to graph y=2%2Ax%2B3


So this is the graph of y=2%2Ax%2B3 through the points (0,3) and (1,5)