SOLUTION: Find the value of k so that the line containing the points (k,0) and (-5,2) is perpendicular to the line y=6/7x-1

Algebra ->  Linear-equations -> SOLUTION: Find the value of k so that the line containing the points (k,0) and (-5,2) is perpendicular to the line y=6/7x-1      Log On


   

Question 956572: Find the value of k so that the line containing the points (k,0) and (-5,2) is perpendicular to the line y=6/7x-1
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+y+=+%28+6%2F7+%29%2Ax+-+1+
The slope is: +m+=+6%2F7+
Any line perpendicular to this
line has slope = +-1%2Fm+
+-1%2Fm+=+-1%2F%286%2F7%29+
+-1%2Fm+=+-7%2F6+
-------------------
( k,0 )
( -5,2 )
The slope is [ change in y ] / [ change in x ]
+%28+2+-+0+%29+%2F+%28+-5+-+k+%29+=+-7%2F6+
+2+%2F+%28+-5+-k+%29+=+-7%2F6+
+2+=+-%287%2F6%29%2A%28+-5+-k+%29+
+2+=+-%287%2F6%29%2A%28+-%28+5+%2B+k+%29%29+
+2+=+%287%2F6%29%2A%28+5+%2B+k+%29+
+5+%2B+k+=+%286%2F7%29%2A2+
+k+=+12%2F7+-+5+
+k+=+12%2F7+-+35%2F7+
+k+=+-23%2F7+
---------------------
check:
+%28+2+-+0+%29+%2F+%28+-5+-+k+%29+=+-7%2F6+
+%28+2+-+0+%29+%2F+%28%28+-5+-%28+-23%2F7+%29+%29%29+=+-7%2F6+
+2+%2F+%28+%28+-35%2F7+%2B+23%2F7+%29+%29+=+-7%2F6+
+2+%2F+%28+-12%2F7+%29+=+-7%2F6+
+2+=+%28+12%2F7%29%2A%287%2F6%29+
+2+=+2+
OK