SOLUTION: The area of a square is 81-90x+25x^2 square meters. If x is a positive integer, what is the least possible perimeter measure for the square?

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Question 956043: The area of a square is 81-90x+25x^2 square meters. If x is a positive integer, what is the least possible perimeter measure for the square?
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
A=area; s=side; P=perimeter=4s
A=s%5E2=81-90x%2B25x%5E2 Re-write for clarity.
s%5E2=25x%5E2-90x%2B81 Find square root of each side.
s=sqrt%2825x%5E2-90x%2B81%29
s=%285x-9%29meters
P=4s=4%285x-9%29meters For x=1, P is negative. For x=2:
P=4%285%282%29-9%29meters=4%281%29meters=4meters
ANSWER: If x is a positive integer, the least possible perimeter is 4 meters.