SOLUTION: How does the graph of y=mx+b + 4 differ from that of y=mx +b ? In what ways are the two graph similar

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Question 952433: How does the graph of y=mx+b + 4 differ from that of y=mx +b ? In what ways are the two graph similar
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

first recall that y=mx+%2Bb is the slope-intercept form of the linear equation where m is a slope and b is y-intercept
the graph of y=mx%2Bb+%2B+4 differ from that of y=mx+%2Bb in y-intercept (the point where the line crosses the y-axis)
this one y=mx%2Bb+%2B+4 has y-intercept b%2B4, and this one y=mx+%2Bbhas y-intercept b; means that the graph of y=mx%2Bb+%2B+4 intercept y-axis 4 units in higher point then the graph of y=mx+%2Bb
but, these two graphs have same slope which is m and that is telling us that lines are parallel
here is one example:
let first equation y=mx%2Bb+%2B+4%7D%7D+be+%7B%7B%7By+=+4x+%2B6%2B4=> the slope is m=4+ and the y-intercept is point (0, 10),
let second equation y=mx%2Bb+%7D%7D+be+%7B%7B%7By+=+4x+%2B6=> the slope is m=4+ and the y-intercept is point (0, 6),
now, graph them to see that these lines are parallel, just their the y-intercept point is different
+graph%28+600%2C+600%2C+-15%2C+15%2C+-15%2C+15%2C+4x+%2B6%2C+4x+%2B10%29+