SOLUTION: The line perpendicular to 3x-4=12 with a y-intercept of 8

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Question 950065: The line perpendicular to 3x-4=12 with a y-intercept of 8
Found 2 solutions by Fombitz, Alan3354:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
A line perpendicular to
3x-4=12
3x=16
x=16%2F3
would have the form, y=b
So then,
y=8

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The line perpendicular to 3x-4=12 with a y-intercept of 8
3x-4=12
3x = 16
x = 16/3 is a "vertical" line (parallel to the y-axis)
Perpendicular lines are parallel to the x-axis and are of the form y = constant
--> y = 8